m^2+23m-22=0

Solution for m^2+23m-22=0 equation:

m^2+23m-22=0

a = 1; b = 23; c = -22;
Δ = b2-4ac
Δ = 232-4·1·(-22)
Δ = 617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{617}}{2*1}=\frac{-23-\sqrt{617}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{617}}{2*1}=\frac{-23+\sqrt{617}}{2}
$